The components of a force acting on a particle are varying according to the graphs shown. When the particle moves from (0, 5,12) to (4,20,0) then the work done by this force is
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a
192 J
b
400/3 J
c
0
d
None of these
answer is A.
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Detailed Solution
From given graphs: F→=34x+10i^+20−43yj^+43z−16k^W=∫F→⋅ds→=∫(0,5,12)(4,20,0) 34x+10i^+20−43yj^+43z−16k^×[dxi^+dyj^+dzk^]=192J