Questions
A composite rod ABC is made of two rods AB and BC of same cross-sectional area. Material of AB has coefficient of thermal conductivity K and that of rod BC is . In steady state , temperature of junction B is
detailed solution
Correct option is C
100−θl/KA=θ−502lkA/2⇒100−θ=θ−504 ⇒θ=90oCTalk to our academic expert!
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A body of length 1 m having cross sectional area has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if K = 200 J
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