Questions

A composite rod consists of a steel rod of length 25 cm and area 2A and a copper rod of length 50 cm and area A. The composite rod is subjected to an axial load F. If the Young's moduli of steel and copper are in the ratio 2:1, then

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the extension produced in copper rod will be more

the extension in copper and steel parts will be in the ratio 1:2

the stress applied to copper rod will be more

no extension will be produced in the steel rod

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detailed solution

Correct option is A

( stress )S=F2A, ( stress )Cu=FAGiven that YSYCu=21( strain )S( strain )Cu=( stress )S/YS( stress )Cu/YCu=( stress )S( stress )Cu×YCuYS=(F/2A)(F/A)×12=14 ΔLS/LSΔLCu/LCu=14 or Lcu ΔLsLs ΔLcu=14 50 ΔLs25 ΔLcu=14 ΔLsΔLcu=18 As area of cross section of steel is more than copper. Stress applied to steel is less than copper

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