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Q.

In a composite rod, when two rods of different lengths and of the same area of cross-section are joined end to end, then if K is the effective coefficient of thermal conductivity, I1+I2K is equal to

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a

I1K1−I2K2

b

I1K2−I2K1

c

I1K1+I2K2

d

I1K2×I2K1

answer is C.

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Detailed Solution

R=R1+R2 ∵ Thermal Resistance R=LkA L1+L2kA=L1k1A+L2k2A ⇒L1+L2k=L1k1+L2k2
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