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In a composite rod, when two rods of different lengths and of the same area of cross-section are joined end to end, then if K is the effective coefficient of thermal conductivity, I1+I2K is equal to 

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a
I1K1−I2K2
b
I1K2−I2K1
c
I1K1+I2K2
d
I1K2×I2K1

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detailed solution

Correct option is C

R=R1+R2 ∵ Thermal Resistance R=LkA L1+L2kA=L1k1A+L2k2A ⇒L1+L2k=L1k1+L2k2


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