First slide
Conduction
Question

A composite slab consists of two plates of thicknesses L1 and L2 and thermal conductivities K1 and K2. The cross-sectional areas are equal. The equivalent thermal conductivity is:

Moderate
Solution

In series connection
Keq=liliKi=L1+L2L1K1+L2K2=K1K2(L1+L2)K2L1+K1L2

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App