In a compound microscope, the magnified virtual image is formed at a distance of 25 cm from the eye-piece. The focal length of its objective lens is 1 cm. If the magnification is 100 and the tube length of the microscope is 20 cm, then the focal length of the eye-piece lens (in cm) is ____________ .
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answer is 0006.25.
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Detailed Solution
Magnification for Near pointM=v0u01+DfePractically , we write, u0=f0 and v0=ℓM ≈ℓf01+Dfe Here, ℓf01+Dfe=100⇒2011+25fe=100⇒fe=6.25 cm
In a compound microscope, the magnified virtual image is formed at a distance of 25 cm from the eye-piece. The focal length of its objective lens is 1 cm. If the magnification is 100 and the tube length of the microscope is 20 cm, then the focal length of the eye-piece lens (in cm) is ____________ .