Questions
In a compound microscope the objective lens and eye piece have focal length of 0.95 cm and 5 cm respectively, and are kept at a distance of 20 cm. The last image is formed at a distance of 25 cm from the eye piece calculate magnifying power:
detailed solution
Correct option is A
f0=0.95 m=V0u01+Dfefe=5cm ue=256For eyepiece1+Dfe=VeUe u=Ve6V0=20−256=956m0=956−0.950.95≈946mnet =946×6=94Talk to our academic expert!
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