Compressibility of water is 5×10−10m2/N. Find the decrease in volume (in mL) of 100 mL of water when subjected to a pressure of 15 MPa.

The compressibility K is the reciprocal of the bulk modulus. K =∆P∆VVDecrease in volume = ∆v= ∆p v 1k∴ ΔV=−VΔp compressibility=−(100mL)5×10−10m2/N15×106N/m2=−0.75mLThe decrease in volume is thus 0.75 mL.