The compressibility of water is 4×10−5 per unit atmospheric pressure. The decrease in volume of 100 cm3 of water, under a pressure of 100 atmosphere, will be
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a
0.4 cm3
b
4×10−5cm3
c
0.025 cm3
d
0.004 cm3
answer is A.
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Detailed Solution
K=4×10−5 per unit atm OP = 100 atmB=1K=−OP/ΔVV⇒ΔV=ΔP×x×VΔV=100×4×10−5×100=0.4 cm3