The compressibility of water is 4×10−5 per unit atmospheric pressure. The decrease in volume of 100 cm3 of water, under a pressure of 100 atmosphere, will be

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0.4 cm3

4×10−5cm3

0.025 cm3

0.004 cm3

answer is A.

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Detailed Solution

K=4×10−5 per unit atm OP = 100 atmB=1K=−OP/ΔVV⇒ΔV=ΔP×x×VΔV=100×4×10−5×100=0.4 cm3

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