A concave mirror of focal length 15 cm forms an image having twice the linear dimensions of the object. The position of the object when the image is virtual will be
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a
22.5 cm
b
7.5 cm
c
30 cm
d
45 cm
answer is B.
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Detailed Solution
f=−15cm, m=+2 (Positive because image is virtual) ∵m=−vu⇒v=−2u. By using mirror formula 1−15=1(−2u)+1u⇒u=−7.5cm