A concave mirror of radius of curvature h is placed at the bottom of a tank containing a liquid of refractive index μ up to a depth d. An object P is placed at height h above the bottom of the mirror. Outside the liquid, an observer O views the object and its image in the mirror. The apparent distance between these two will be

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h1−1μ

2hμ−1

zero

2hμ

answer is C.

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Detailed Solution

There will be two images on by direct observation other by reflection through mirror. Apparent depth = Real depth μrel = Real depth μincident μrefractive =(d−h)(μ/1)dapp=(d−h)μObject P is placed at the centre of curvature of the mirror. Its image will be formed at P itself. So, for image also, dapp =(d−h)μ−(d−h)μ=0

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