A concrete sphere of radius R has a cavity of radius r which is packed with sawdust. The specific gravities of concrete and sawdust are respectively $$2.4$$ and $$0.3$$ for this sphere to float with its entire volume submerged under water. Ratio of mass of concrete to mass of sawdust willbe

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Infinity Learn · Accepted Answer

Let specific gravities of concrete and saw dust are ρ$$1$$ and ρ$$2$$ respectively.According to principle of floatation weight of whole sphere $$=$$ upthrust on the $$sphere43$$π(R3-r3)ρ$$1g+43$$$$π$$$$r3$$ρ$$2g$$ $$=$$ $$43$$$$π$$$$R3$$×$$1$$×g⇒$$R3$$ρ$$1-r3$$ρ$$1+r3$$ρ$$2$$ $$=$$ $$R3$$⇒$$R3($$ρ$$1-1)$$ $$=$$ $$r3($$ρ$$1-$$ρ$$2)$$⇒$$R3r3$$ $$=$$ ρ$$1-$$ρ$$2$$ρ$$1-1$$⇒$$R3-r3r3$$ $$=$$ ρ$$1-$$ρ$$2-$$ρ$$1+1$$ρ$$1-1$$⇒(R3-r3)ρ$$1r3$$ρ$$2$$ $$=$$ (1-$$ρ$$2$$ρ$$1-1)ρ$$1$$ρ$$2$$⇒Mass of concreteMass of saw dust $$=$$ (1-0.32.4-1) ×$$2.40.3$$ $$=$$ $$4$$

A concrete sphere of radius R has a cavity of radius r which is packed with sawdust. The specific gravities of concrete and sawdust are respectively 2.4 and 0.3 for this sphere to float with its entire volume submerged under water. Ratio of mass of concrete to mass of sawdust willbe

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