First slide

Capacitance

Question

A condenser of capacity “C” is charged to a potential “V” and connected to an uncharged condenser of capacity “C”. The loss of energy during the sharing of the charges is

Moderate

A

$\frac{C V^{2}}{4}$
B

$\frac{C V^{2}}{2}$
C

$\frac{3 C V^{2}}{4}$
D

$\frac{C V^{2}}{8}$

Solution

$e n e r g y l o s s ∆ E = \frac{1}{2} \frac{C_{1} C_{2}}{C_{1} + C_{2}} {(V_{1} - V_{2})}^{2} h e r e V_{1} = V a n d V_{2} = 0 ∆ E = \frac{C V^{2}}{4}$

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