Questions
A condenser of capacity “C” is charged to a potential “V” and connected to an uncharged condenser of capacity “C”. The loss of energy during the sharing of the charges is
a
CV24
b
CV22
c
3CV24
d
CV28
detailed solution
Correct option is A
energy loss ∆E=12C1C2C1+C2V1-V22 here V1 =V and V2= 0 ∆E =CV24Talk to our academic expert!
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