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A condenser of capacity 6μF is fully charged using a 6 volt battery. The battery is removed and a resistanceless 0.2 mH inductor is connected across the condenser. The current which is flowing through the inductor when one-third of the total energy is in the magnetic field of the inductor is :

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a

0.1 A

b

0.2 A

c

0.4 A

d

0.6 A

answer is D.

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Detailed Solution

Total energy = Initial energy on capacitor = 12CV2Magnetic field energy = 12LI2∴12LI2=13 x 12CV2 ⇒I=CV23L=6 x 10-6 x 6 x 63×0.2×10-3=0.6 A

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A condenser of capacity 6μF is fully charged using a 6 volt battery. The battery is removed and a resistanceless 0.2 mH inductor is connected across the condenser. The current which is flowing through the inductor when one-third of the total energy is in the magnetic field of the inductor is :