A condenser of capacity 6μF is fully charged using a 6 volt battery. The battery is removed and a resistanceless 0.2 mH inductor is connected across the condenser. The current which is flowing through the inductor when one-third of the total energy is in the magnetic field of the inductor is :

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

0.1 A

0.2 A

0.4 A

0.6 A

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Total energy = Initial energy on capacitor = 12CV2Magnetic field energy = 12LI2∴12LI2=13 x 12CV2 ⇒I=CV23L=6 x 10-6 x 6 x 63×0.2×10-3=0.6 A

Watch 3-min video & get full concept clarity