Questions
A condenser has two conducting plates of radius separated by a distance of . It is charged with a constant current of . The magnetic field at a point from the axis in the gap is
detailed solution
Correct option is C
Consider a loop of radius 'r' between the two circular plates, placed axially with them. The area of the loop, A'=πr2 By symmetry magnetic field induction B→ is equal in magnitude and is tangential to the circle at every point In this case, only displacement current ID, will cross the loop. Therefore, using Ampere’s Maxwell law, we have ∮B→.dl→=μ0ID⇒2πrB=μ0×(current passing through the area A') ⇒ 2πrB=μ0Iπr2πR2 ⇒B=μ0ID2πr×rR2 ⇒ B=μ0I2π×rR2 ⇒B=2×10−7×0.15×2×10−210−2 ⇒ B=6×10−8TTalk to our academic expert!
Similar Questions
A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400 V. if the plate area is 60 , then the value of displacement current for will be
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