A conducting loop having a capacitor is moving outward from the magnetic field then which plate of the capacitor will be positive
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a
Plate – A
b
Plate – B
c
Plate – A and Plate – B both
d
None
answer is A.
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Detailed Solution
Crosses (x) linked with the loop are decreasing, so induced current in it is clockwise i.e. from B → A. Hence electrons flow from plate A to B so plate A becomes positively charged