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A conducting ring of mass 2 kg and radius 0.5 m is placed‘on a smooth horizontal plane. The ring carries a current of I =4A. A horizontal magnetic field B = 10 T is switched on at time t = 0 as shown in figure. The initial angular acceleration of the ring will be

a
40πrads-2
b
20πrads-2
c
5πrads-2
d
15πrads-2

detailed solution

Correct option is A

Due to torque of magnetic field, ring will rotate about vertical diameterτ=Iα⇒MB=Iα ⇒  iπr2B=12mr2α ⇒  α=2iBπm=2×4×10π2=40πrads-2

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Similar Questions

A non-conducting non-magnetic rod having circular cross section of radius R is suspended from a rigid support as shown in the figure. A light and small coil of 300 turns is wrapped tightly at the left end of the rod where uniform magnetic field B exists in vertically downward direction.Air of density ρ hits the half of the right part of the rod with velocity V as shown in the figure. What should be current in clockwise direction (as seen from O) in the coil so that rod remains horizontal? Give answer in m A. Given

2LvπRBρ=15 A-1/2


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