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Q.

A conducting ring of mass 2 kg and radius 0.5 m is placed on a smooth horizontal plane. The ring carries a current of  i=4 A. A horizontal magnetic field B=10 T is switched on at time t=0 as shown in figure. The initial angular acceleration of the ring will be

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a

40π rad s-2

b

20π rad s-2

c

5π rad s-2

d

15π rad s-2

answer is A.

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Detailed Solution

Due to torque of magnetic field, ring will rotate about vertical diameter. τ=Iα ⇒MBsin90o=Iα⇒iπr2B=12mr2α⇒α=2iBπm=2×4×10π2=40πrad s-2.
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