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Q.

A conducting ring of radius a falls vertically downward with a velocity v in a uniform horizontal magnetic field B. The potential difference between two points P and Q located symmetrically on both sides of the vertical has the value

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a

0

b

Bv0a2

c

32Bv0a

d

Bv0a

answer is D.

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Detailed Solution

Linear distance between P and Q ,l= 2×2a sin 300=aTherefore induced emf = Blv=Bav0
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A conducting ring of radius a falls vertically downward with a velocity v in a uniform horizontal magnetic field B. The potential difference between two points P and Q located symmetrically on both sides of the vertical has the value