A conducting ring of radius $$1$$ m is placed in a uniform magnetic field B of $$0.01$$ T oscillating with frequency $$100$$ Hz with its plane at right angle to B. What will be the induced electric field?

Question

Infinity Learn · Accepted Answer

From Faraday's law of electromagnetic induction, the induced emf is equal to negative rate of change of magnetic flux.That is $$e=$$−ΔϕΔtFlux induced $$=2BA$$ $$cos$$θwhere B is magnetic field, A is area. Given, θ$$=0$$∘, Δ$$t=1100$$ sΔϕ$$=2$$×$$0.01$$×π×$$(1)2$$×$$200$$×$$cos0$$∘∴ $$e=$$−$$2$$×$$0.01$$×π×$$(1)2$$×$$200100=$$−$$4$$π volt Circumference of a circle of radius r  is  $$2$$ πr. ∴   Induced electric field E $$isE=$$|e|$$2$$$$π$$$$r=4$$$$π$$$$2$$$$π$$$$r=21=2V/m$$

A conducting ring of radius 1 m is placed in a uniform magnetic field B of 0.01 T oscillating with frequency 100 Hz with its plane at right angle to B. What will be the induced electric field?

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