A conducting ring of radius r is rolling without slipping with a constant angular velocity ω (figure). If the magnetic field strength is B and is directed into the page then the emf induced across PQ is

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Bωr2

Bωr22

4Bωr2

π2r2Bω8

answer is A.

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Detailed Solution

Join PQ with an imaginary line which is instantaneously rotating with ω about point Q.|E|= Magnitude of induced emf =Bℓ22ω here ℓ=2r⇒E=B2r2ω2=Bωr2

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