A conducting ring of radius r is rolling without slipping with a constant angular velocity ω (figure). If the magnetic field strength is B and is directed into the page then the emf induced across PQ is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
Bωr2
b
Bωr22
c
4Bωr2
d
π2r2Bω8
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Join PQ with an imaginary line which is instantaneously rotating with ω about point Q.|E|= Magnitude of induced emf =Bℓ22ω here ℓ=2r⇒E=B2r2ω2=Bωr2