First slide
Magnetic flux and induced emf
Question

A conducting rod of length l is falling with a velocity v perpendicular to a uniform horizontal magnetic field B. The potential difference between its two ends will be

Moderate
Solution

F=qE qvB=qemfl ε=Blv

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App