Questions
A conducting rod of length is hinged at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field in horizontal direction. The rod is released from the horizontal position as shown. The potential difference between the ends of the rod when it has turned by (as shown in figure) is proportional to
detailed solution
Correct option is D
The induced electro motive force Δv across ends of rotating rod about one end in magnetic field =B2l2ω .ω can be calculated according to law of conservation energy.Increase in rotational kinetic energy = decrease in gravitational potential energy 12Iω2=mgh⇒12ml23ω2=mg.l2sinθ⇒ω=3glsinθNow ΔV=12Bl23glsinθ ……( 1 )∴ΔV∝sinθAlso from ( 1 ), ΔV∝l32Therefore, the correct answer is ( D )Talk to our academic expert!
Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests