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A conducting rod of length l  is hinged at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field B  in horizontal direction. The rod is released from the horizontal position as shown. The potential difference between the ends of the rod when it has turned by θ (as shown in figure) is proportional to

a
l1/2
b
l2
c
sinθ
d
sinθ1/2

detailed solution

Correct option is D

The induced electro motive force Δv across ends of rotating rod about one end in magnetic field =B2l2ω .ω can be calculated according to law of conservation energy.Increase in rotational kinetic energy = decrease in gravitational potential energy  12Iω2=mgh⇒12ml23ω2=mg.l2sinθ⇒ω=3glsinθNow    ΔV=12Bl23glsinθ ……( 1 )∴ΔV∝sinθAlso from ( 1 ),  ΔV∝l32Therefore, the correct answer is ( D )

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Similar Questions

The diagram shows a circuit having a coil of resistance R=2.5Ω and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.

At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.


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