Q.

A conducting rod of length L is moving on a horizontal smooth surface. Magnetic field in the region is vertically downward and of magnitude B0. If center of mass of the rod O is translating at a speed v0  and rod rotates about center of mass with angular speed v0L  then the potential difference between points O and end point A is B0v0Ln. Find n.

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answer is 1.60.

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Detailed Solution

Due to polarity of motional emf between O and A,etotal=B0L2v0+L4v0L=5B0Lv08=B0v0L1.6      induced emf   due to translatory motion and due to rotatory motion n=1.6
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A conducting rod of length L is moving on a horizontal smooth surface. Magnetic field in the region is vertically downward and of magnitude B0. If center of mass of the rod O is translating at a speed v0  and rod rotates about center of mass with angular speed v0L  then the potential difference between points O and end point A is B0v0Ln. Find n.