A conducting rod of length 2l is rotating with constant angular speed ω about its perpendicular bisector. A uniform magnetic field B→ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is
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a
Bωl2
b
12Bωl2
c
18Bωl2
d
Zero
answer is D.
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Detailed Solution
Potential difference between O and A isV0-VA=12Bl2ωPotential difference between O and B isVo-VB=12Bl2ω so VA-VB=0