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Q.

A conducting rod of length / and mass m is moving down a smooth inclined plane of inclination θ with constant velocity v. A current i is flowing in the conductor in a direction perpendicular to paper inwards. A vertically upward magnetic field B→ exists in space. Then, magnitude of magnetic field B→ is

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a

mg il sinθ

b

mgiltanθ

c

mgcosθil

d

mgilsinθ

answer is B.

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Detailed Solution

Magnetic force acts in the direction shown in figureRod will move downward with constant velocity if net force on it is zero. or   Fmcosθ=mgsinθ  or   ilBcosθ=mgsinθ ∴  B=mgiltanθ
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