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Q.

A conducting rod PQ of length L = 1 m is moving with a uniform speed v = 2.0 m s-1 in a uniform magnetic field B = 4.0 T directed into the plane of the paper.A capacitor of capacity C=10μF is connected as shown in figure, then

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a

qA=+80μC and qB=-80μC

b

qA=-80μC and qB=+80μC

c

qA=0=qB

d

charge stored in the capacitor increases exponentially with time

answer is A.

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Detailed Solution

q =CV=C(Bvl)= (10 x 10-6) (4) (2) (1)=80μC=constantMagnetic force on the electron in the conducting rod PQ is towards Q.Therefore, A is positively charged and B is negatively charged.
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