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Questions  

A conducting rod PQ of length 1 m is moving with uniform speed of 2 ms-1 in a uniform magnetic field 4 T directed into the plane of paper. A capacitor of capacity 10 μF is connected as shown. Then,

a
current flows along PQ
b
qA=80μ/C,qB=−80μC
c
qA=−80μC,qB=80μC
d
qA=qB=80μC

detailed solution

Correct option is C

e= Blv =4×1×2=8q=CV=10μF×8=80μCqA=80μC,qB=−80μC

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