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Q.

A conducting solid sphere having uniform charge Q on it has radius R. It is rotating with an angular velocity ω.  If a uniform magnetic field B is present perpendicular to axis of rotation then the torque on sphere will be

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a

qωR25B

b

qωR23B

c

qωR28B

d

qωR22B

answer is B.

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Detailed Solution

Magnetic moment of sphere is M thenM23mR2ω=q2m⇒M=qωR23 Torque =MBsin⁡90∘=qωR2B3
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