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Questions  

A conducting solid sphere having uniform charge Q on it has radius R. It is rotating with an angular velocity ω If a uniform magnetic field B is present perpendicular to axis of rotation then the torque on sphere will be

a
qωR25B
b
qωR23B
c
qωR28B
d
qωR22B

detailed solution

Correct option is B

Magnetic moment of sphere is M thenM23mR2ω=q2m⇒M=qωR23 Torque =MBsin⁡90∘=qωR2B3

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