A conducting solid sphere having uniform charge Q on it has radius R. It is rotating with an angular velocity ω. If a uniform magnetic field B is present perpendicular to axis of rotation then the torque on sphere will be
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a
qωR25B
b
qωR23B
c
qωR28B
d
qωR22B
answer is B.
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Detailed Solution
Magnetic moment of sphere is M thenM23mR2ω=q2m⇒M=qωR23 Torque =MBsin90∘=qωR2B3