Questions
A conducting square frame of side ‘a’ and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity ' V '. The emf induced in the frame will be proportional to
detailed solution
Correct option is B
Here, P Q = R S = P R = Q S = aEmf induced in the frame ε=B1(PQ)V-B2(RS)V=μ0I2π(x-a/2)aV-μ0I2π(x+a/2)aV=μ0I2π2(2x-a)-2(2x+a)aV=μ0I2π×22a(2x-a)(2x+a)aV∴ ε∝1(2x-a)(2x+a)Talk to our academic expert!
Similar Questions
A copper rod AB of length 2m is moving in a uniform magnetic field of 1.5 T with a velocity of 3 m/s. The induced potential difference between ends A and B is
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