Questions
A conducting square frame of side 'a' and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to :
detailed solution
Correct option is C
emf induced in side (I)ε1 = B1 Vlemf induced in side (2)ε2 = B2 Vlemf in the frame = B1 Vl - B2 Vlε=VlB1-B2 ⇒ε∝B1-B2 Since, B∝1r,So, ε∝1x-a2-1x+a2⇒ε∝12x-a-12x+aTalk to our academic expert!
Similar Questions
A conducting rod PQ of length 1 m is moving with uniform speed of 2 ms-1 in a uniform magnetic field 4 T directed into the plane of paper. A capacitor of capacity 10 F is connected as shown. Then,
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
