A conducting wire ABC (as$$ $$shown) is moving with a constant velocity along hoirzontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB $$=$$ BC. Find the range of angle θ made by rod AB with horizontal at A so that value of induced emf at A is greater than at C.

Question

A conducting wire ABC (as$$ $$shown) is moving with a constant velocity along hoirzontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB $$=$$ BC. Find the range of angle θ made by rod AB with horizontal at A so that value of induced emf at A is greater than at C.

Infinity Learn · Accepted Answer

Let AB $$=$$ BC $$=$$ lVelocity $$=$$ vMagnetic field $$-$$ B $$E1=$$ Bv l $$sin$$θ$$E2=$$ Bv I $$cos$$θFor induced emf at A > induced emf at $$BE2$$ > $$E1Bv$$ I $$($$$$cos$$θ $$-$$ $$sin$$θ$$)$$ > $$0cos$$θ > $$sin$$θ $$+$$ $$tan$$θ < $$1$$θ < $$450$$

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A conducting wire ABC (as shown) is moving with a constant velocity along hoirzontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB = BC. Find the range of angle θ made by rod AB with horizontal at A so that value of induced emf at A is greater than at C.

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