A conducting wire ABC (as shown) is moving with a constant velocity along hoirzontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB = BC. Find the range of angle θ made by rod AB with horizontal at A so that value of induced emf at A is greater than at C.

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θ>450

θ<450

θ>600

θ<750

answer is B.

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Detailed Solution

Let AB = BC = lVelocity = vMagnetic field - B E1= Bv l sinθE2= Bv I cosθFor induced emf at A > induced emf at BE2 > E1Bv I (cosθ - sinθ) > 0cosθ > sinθ + tanθ < 1θ < 450

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