A conducting wire of length l and mass m can slide without friction on two parallel rails and is connected to capacitance C. The whole system lies in a magnetic field B and a constant force F is applied to the rod. Then
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a
the rod moves with constant velocity
b
the rod moves with an acceleration of (F)/m+B2l2C
c
there is constant charge on the capacitor
d
charge on the capacitor increases with time
answer is B.
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Detailed Solution
i=dqdt=ddt(CvBl)=CBldvdt=CBla∴F−CB2l2a=ma⇒a=Fm+B2l2C⇒ emf increases as velocity v increases with time and emf = Blv⇒ charge increases.