Q.

A conducting wire of mass m slides down two smooth conducting bars, set at an angle θ to the horizontal as shown in figure. The separation between the bars is l. Thesystem is located in the magnetic field B, perpendicular to the plane of the sliding wire and bars. The constant velocity of the wire is

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a

mgRsin⁡θB2l2

b

mgRsin⁡θBl3

c

mgRθB2l5

d

mgRsin⁡θBl4

answer is A.

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Detailed Solution

Component of weight along the inclined plane = mg sin θ Again, Fm=Bil=BBlvRl=B2l2vRFor constant velocity, the magnetic force is balanced by component of weight along the inclined plane. Now, B2l2vR=mgsin⁡θ  or  v=mgRsin⁡θB2l2
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