Q.

A conducting wire of mass m slides down two smooth conducting bars, set at an angle θ to the horizontal as shown in figure. The separation between the bars is l. Thesystem is located in the magnetic field B, perpendicular to the plane of the sliding wire and bars. The constant velocity of the wire is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

mgRsin⁡θB2l2

b

mgRsin⁡θBl3

c

mgRθB2l5

d

mgRsin⁡θBl4

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Component of weight along the inclined plane = mg sin θ Again, Fm=Bil=BBlvRl=B2l2vRFor constant velocity, the magnetic force is balanced by component of weight along the inclined plane. Now, B2l2vR=mgsin⁡θ  or  v=mgRsin⁡θB2l2
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon