Q.

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is

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a

0

b

1.41 volt

c

0.71 volt

d

None of the above

answer is B.

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Detailed Solution

There is no induced emf in the part AB and CD because they are moving along their length while emf induced between B and C i.e. between A and D can be calculated as followsInduced emf between B and C = Induced emf between A and B= Bv(2 l)=1×1×1×2=1.41 volt.
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A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is