Questions
A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 Wb/m2, as shown in fig. If all the four sides are of 1 m length each, then the induced emf between points A and D is
detailed solution
Correct option is B
There is no induced e.m.f. in the part AB and CD because they are moving along their length while e.m.f. induced between B and C, i.e., between A and D can be calculated as follows:Induced e.m.f. between B and C = Induced e.m.f. between A and D=Bv(2l)=1×1×1×2=1.41 voltsTalk to our academic expert!
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A copper rod AB of length 2m is moving in a uniform magnetic field of 1.5 T with a velocity of 3 m/s. The induced potential difference between ends A and B is
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