First slide

Motional EMF

Question

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 Wb/m², as shown in fig. If all the four sides are of 1 m length each, then the induced emf between points A and D is

Moderate

A

0
B

1.41 volt
C

0.71 volt
D

None of these

Solution

There is no induced e.m.f. in the part AB and CD because they are moving along their length while e.m.f. induced between B and C, i.e., between A and D can be calculated as follows:
Induced e.m.f. between B and C = Induced e.m.f. between A and D
$= Bv (\sqrt{2} l) = 1 \times 1 \times 1 \times \sqrt{2} = 1.41 volts$

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