A conductor is bent in the form of concentric semicircles as shown in the figure. The magnetic field at the point common center O is
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a
zero
b
μ0I6a
c
μ0Ia
d
μ0I4a
answer is B.
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Detailed Solution
magnetic field for a semicircle B=μ0i4r here B=μoi4a1-12+14-18+116-132......... B= μoi4a1+14+116+164......-μoi4a21+14+116+164........ B =μoi4a43-μoi8a43=μoi6a