A conductor carries a constant current I along the closed path abcdefgha involving 8 of the 12 edges of length l . Find the magnetic dipole moment of the closed path.
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a
l2Ij^
b
l2I k^
c
l2I2 j^
d
l2I −j^
answer is A.
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Detailed Solution
Closed path is a superposition of the loops bcfgb, abgha, and cdefc.∴The magnetic moments of the three loops areloop -1(bcfgb) m¯1=i l2j^ loop -2 (abgha) m¯2=−l2i i^ loop - 3(cdefc) m¯3=+l2i i^ ∴ M¯net=M¯1+M¯2+M¯3 = i l2j^−l2i i^+l2i i^= i l2j^