A cone lies in a uniform electric field E as shown in figure. The electric flux entering the cone is
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a
EπR2
b
ERh
c
EhR2
d
Eh2
answer is B.
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Detailed Solution
Plane normal to electric field is a triangle with base length 2R and height h.Area of triangle A = 12 x 2Rh = RhElectric flux entering the cone = EA = ERh