First slide

Electric Flux

Question

A cone lies in a uniform electric field E as shown in figure. The electric flux entering the cone is

Moderate

A

${EπR}^{2}$
B

ERh
C

$\frac{ERh}{2}$
D

$\frac{{Eh}^{2}}{2}$

Solution

The effective area through which the flux is entering the cone is a triangle with base 2R and height h.
Area of triangle $A = \frac{1}{2} \times 2 R \times h = Rh$
Electric Flux $= EA = ERh$

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