A cone lies in a uniform electric field E as shown in figure. The electric flux entering the cone is
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a
EπR2
b
ERh
c
ERh2
d
Eh22
answer is B.
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Detailed Solution
The effective area through which the flux is entering the cone is a triangle with base 2R and height h.Area of triangle A=12×2R×h=RhElectric Flux = EA =ERh