First slide

Capacitance

Question

Consider an arrangement of six plates of effective area A and separated from each other by distance d as shown. The capacitance between terminals of A and B

Moderate

A

$6 A ϵ_{0} / d$
B

$3 A ϵ_{0} / 2 d$
C

$7 A ϵ_{0} / 2 d$
D

$5 A ϵ_{0} / d$

Solution

The resultant of the above circuit has 5 capacitors of capacitance = $\frac{A ε_{0}}{d}$ in parallel. Hence the equivalent capacitance becomes $\frac{5 A ε_{0}}{d}$

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