Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Consider an attractive central force of the form F(r)=−krn,k is a constant. For a stable circular orbit to exist.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

n=2

b

n<3

c

n>3

d

n=-1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

F(r)=−krn⇒U(r)=−∫F(r)dr=−k(n−1)⋅1rn−1 Kinetic energy =L22I=L22mr2=K(r) Since total energy E(r)=U(r)+K(r)⇒E(r)=−k(n−1)⋅1rn−1+L22mr2⇒∂Earr=p=0 and ∂2E∂r2r=D>0, Using both conditions, (3−n)L2m>0
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring