Consider a body executes periodic motion given by  2sin2t+π4m. Then we can  concluded that

The given equation 2sin2t+π4 can be compared with  y=A​  sin(ω  t+ϕ). This  shows that the body executes a simple harmonic motion. Time period can be  determined from  'ω' of the given equation. On comparison of  2sin2t+π4 with   A​  sin(ω  t+ϕ)., We get  ω=2  rad  s−1,A=2mWe know that ω=2πt=2πT&ϕ=π4∴2=2πTT=πsHence, We condude that time period T=πs amplitude A=2m and phase  ϕ=π4