Consider the circuit shown in the figure. The current I is equal to

Suppose current through different paths of the circuit is as follows.After applying KVL for loop (1) and loop (2), We get28 i1=6−8 ⇒i1=−12Aand  54i2  =−6−12  ⇒  i2=−13 AHence i3 =i1 +i2 =−56 AAs per the question,  I= i3=−56 A