First slide

KVL

Question

Consider the circuit shown in the figure. The current I is equal to

Moderate

A

5 A
B

3 A
C

$- 3 A$
D

$- 5 / 6 A$

Solution

Suppose current through different paths of the circuit is as follows.
After applying KVL for loop (1) and loop (2), We get
$28 i_{1} = 6 - 8 \Rightarrow i_{1} = - \frac{1}{2} A$
$and 54 i_{2} = - 6 - 12 \Rightarrow i_{2} = - \frac{1}{3} A$
Hence $i_{3} = i_{1} + i_{2} = - \frac{5}{6} A$
As per the question, $I = i_{3} = - \frac{5}{6} A$

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