Questions

Consider the circuit shown in the figure. The current I is equal to

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5 A

3 A

−3 A

−5/6 A

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detailed solution

Correct option is D

Suppose current through different paths of the circuit is as follows.After applying KVL for loop (1) and loop (2), We get28 i1=6−8 ⇒i1=−12Aand 54i2 =−6−12 ⇒ i2=−13 AHence i3 =i1 +i2 =−56 AAs per the question, I= i3=−56 A

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