Q.

Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K, respectively. The equivalent thermal conductivity of the slab is:

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a

23K

b

2K

c

3K

d

43K

answer is D.

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Detailed Solution

Keq=∑li∑liki=l+llk+l2k=4K3Keff=2k1k2k1+k2=2×k×2kk+2k=4k3
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Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K, respectively. The equivalent thermal conductivity of the slab is: