First slide

Conduction

Question

Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is

Moderate

A

$\sqrt{2} K$
B

3K
C

$\frac{4}{3} K$
D

$\frac{2}{3} K$

Solution

$K = \frac{2 K_{1} K_{2}}{K_{1} + K_{2}} = \frac{2 . K . 2 K}{K + 2 K} = \frac{4}{3} K$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App