Questions
Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is
a
2K
b
3K
c
43 K
d
23 K
detailed solution
Correct option is C
K = 2K1K2K1+K2 = 2.K.2KK+2K = 43 KTalk to our academic expert!
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