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Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slabs taken in series is 

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By Expert Faculty of Sri Chaitanya
a
25K
b
3K
c
2K
d
43K
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detailed solution

Correct option is D

resistance in series is Rseries=R1+R2 where R = lKA, here l is thickness or length, A is area of cross section,  K is coefficient of thermal conductivity when 2 slabs of different coefficient of thermal conductivity K,2K ,  having same thickness and area of cross section are taken in series effective thermal conductivity is Kseries, given by, l+lKseries=lK+l2K ⇒2Kseries=32K ⇒Kseries=43K


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Two rods of length d1 and d2 and coefficients of thermal conductivities K1 and K2 are kept touching each other. Both have the same area of cross-section. The equivalent of thermal conductivity is

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