Questions
Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slabs taken in series is
detailed solution
Correct option is D
resistance in series is Rseries=R1+R2 where R = lKA, here l is thickness or length, A is area of cross section, K is coefficient of thermal conductivity when 2 slabs of different coefficient of thermal conductivity K,2K , having same thickness and area of cross section are taken in series effective thermal conductivity is Kseries, given by, l+lKseries=lK+l2K ⇒2Kseries=32K ⇒Kseries=43KSimilar Questions
Two rods of length and and coefficients of thermal conductivities and are kept touching each other. Both have the same area of cross-section. The equivalent of thermal conductivity is
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