Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength λ of that electron as
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a
(0.259) nλ
b
nλ
c
(13.6) λ
d
nλ
answer is D.
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Detailed Solution
According to Bohr’s theory mvr=nh2π⇒Circumference 2πr=n hmv=nλ