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Q.

Consider a force  F→=−xi^+yj^ . The work done by this force in moving a particle from point  A1,0 to  B0,1 along the line segment is (all quantities are in SI units)

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a

12

b

32

c

1

d

2

answer is C.

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Detailed Solution

Let ds→=dxi^+dyj^+dzk^             Then, work done=dw=F→.ds→ ⇒W=∫ (−xi^+yj^).(dxi^+dyj^+dzk^) ⇒W=∫ (−xdx+ydy) ⇒W=− 10xdx+ 01ydy ⇒W=−(0−12)+(12−0) =1 J
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