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Consider a hydrogen atom with its electron in the nth orbital. An electromagnetic radiation of wavelength 90nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4eV , then the value of n is (hc=1242eVnm)

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answer is 2.

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Detailed Solution

Energy incident =Einc=hCλinc=1242 90=13.8 eV By law of conservation of energy,Energy of the ejected electron +13.6eVn2= Energy incident⇒10.4eV+13.6eVn2=13.8eV⇒13.6eVn2=3.4⇒n2=4⇒n=2

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Consider a hydrogen atom with its electron in the nth orbital. An electromagnetic radiation of wavelength 90nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4eV , then the value of n is (hc=1242eVnm)